3.5x^2+9.8-480x=0

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Solution for 3.5x^2+9.8-480x=0 equation:



3.5x^2+9.8-480x=0
a = 3.5; b = -480; c = +9.8;
Δ = b2-4ac
Δ = -4802-4·3.5·9.8
Δ = 230262.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-\sqrt{230262.8}}{2*3.5}=\frac{480-\sqrt{230262.8}}{7} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+\sqrt{230262.8}}{2*3.5}=\frac{480+\sqrt{230262.8}}{7} $

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